Otago HSFY chat - archive

[Cathay]

Is question 9 from the 2011 chem terms test something specific to ATP and the lecture we missed? Otherwise would some please explain the answer to me? Cheers

It would help to have had that lecture, but nevertheless you should understand the principles of delta G vs delta G standard vs equilibrium. Lecture 5 can tell you a bit more.

 

[Nimbus2000]

Oh yeah I already have, we did it during the lab, it's just that I can only remember my restreamed lab is Tuesday and not what week it is haha

hey rurururuth, did you manage to find out which week your lab has been rescheduled to because I'm having the same problem haha.

guys all the rescheduled labs are next week, during the week of ANZAC day

I think it went pretty well, had enough time to check everything although there were a couple questions I wan't totally sure on. Fingers crossed!

you are a SUPERBEING! how on earth did you get time to check through everything? lol i spent like 50 minutes on the actual test and then only had 10 minutes to go over everything :/

lol yea, thank goodness for multi-choice!

does anyone recall the lecturer's/slides saying that EM waves travel at the speed of light?

nope, although I should look again. lol. i thanked year 11 physics profusely for making us do c = f(lamda) for EM waves.

Anyone else find the test hard? I thought it was pretty hard, although do-able. THANK GOD there were no heat transfer questions. those questions, give me the SHITS.

 

[keypadlocked]

Hey,

Just wondering if anyone knows how to do question 2 for the 2011 midsemester paper for chem?

2. What volume of water must be added to a solution of 6.00 mol L-1 HNO3 in order to prepare 500 mL of 0.200 mol L-1 HNO3?(A) 600 mL
(B) 167 mL
(C) 500 mL
(D) 483 mL

If so, could you please show me how you work it out?
Cheers ^_^

 

[Nimbus2000]

erm guys... what did you guys get for the mmHg question? Did anyone get 33mmHg ish? *prays*

Hey,

Just wondering if anyone knows how to do question 2 for the 2011 midsemester paper for chem?

2. What volume of water must be added to a solution of 6.00 mol L-1 HNO3 in order to prepare 500 mL of 0.200 mol L-1 HNO3?(A) 600 mL
(B) 167 mL
(C) 500 mL
(D) 483 mL

If so, could you please show me how you work it out?
Cheers ^_^

hey rawry, you can use the formula c1V1 = c2V2

so:
6 * V1 = 0.2 * 0.5
therefore V1 = 0.1 / 6 = 0.0167 L = 16.7mL
therefore volume to be added = Vf - Vi = 500 - 16.7 = 483 mL (ish)

 

[Sam]

Lol, I was just reading the minutes from the CELS class rep meeting. Apparently some students had complained about the topic of suicide being brought up during Peter Deardens lecture (Evolution one). I think (?) all he said was that one of the people had ended up killing themselves? Pretty pathetic, if you're doing a course with the intent to go into medicine (as apparently 99% of people in HSFY are) then I think you should be able to deal with topics like that. It's unavoidable in the line of work.

 

[frootloop]

Lol, I was just reading the minutes from the CELS class rep meeting. Apparently some students had complained about the topic of suicide being brought up during Peter Deardens lecture (Evolution one). I think (?) all he said was that one of the people had ended up killing themselves? Pretty pathetic, if you're doing a course with the intent to go into medicine (as apparently 99% of people in HSFY are) then I think you should be able to deal with topics like that. It's unavoidable in the line of work.

People complained about him last year as well. Personally, I think he's brilliant, and people just need to get over it and take everything a little less seriously, but admittedly some of his jokes are a bit further than you might expect from a lecturer at times.
But yes, you're right, if people can't even handle hearing the word 'suicide' in a lecture, then they may wish to think of a career outside of the health field...

 

[Rotors]

Suicide and mental health are very serious issues not to be taken lightly. By WHO numbers [citation needed] mental health will kill more people by 2020 than cardiovascular disease and cancer combined (it might be CVD + trauma / road traffic accidents I am not sure).

One cannot even begin to be physically well if one is not mentally well, "health" is more than the absence of symps

Oh also please do not pass somebody who is saying they are suicidal off as an "attention seeker"

Now that I've had my two cents worth I will once again leave you HSFYers to it

 

[Steve]

Hey can someone help me out? Why is the answer D not B?

7. Calculate ΔfG o(298 K) for HCl(g) using the following data:
½N2(g) + 3/2H2(g) → NH3(g) ΔfGo (298 K) = –16.45 kJ mol-1
½N2(g) + 2H2(g) + ½Cl2(g) → NH4Cl(s) ΔfGo (298 K) = –202.87 kJ mol-1
NH3(g) + HCl(g) → NH4Cl(s) ΔrGo (298 K) = –91.12 kJ mol-1

(A) –310.44 kJ mol-1
(B) –95.30 kJ mol-1
(C) –128.20 kJ mol-1
(D) –277.54 kJ mol-1

 

[Bluerock]

The answer to that one is B .
Reverse 1 and 3, leaving 2 the same.
Adding Enthalpy is (16.45kJ mol + -202.87kJ mol + 91.12kJ mol) = -95.30kJ mol.

 

[Steve]

Yeah I know but on blackboard it says that there's a mistake with question 7 and the answer is D for some reason...

 

[Bluerock]

That's for the practice test they uploaded, the link above it, not the old terms tests. Don't worry, I did the exact same thing!

 

[Sam]

What in the hell was that chemistry lecture today?

 

[Profiterole]

What in the hell was that chemistry lecture today?

start 10 min late.. mumble mumble "Dioxygenases" mumble, mumble "O2 activation, Kinetics, Lipid membrane, Peroxides" mumble mumble "Here's a formula that you don't need to know" .... "we can trap intermediates! (probably the most interesting thing in the lecture"

Yea, that's what I got from it......


Time to re-watch the lecture (x.x) over a beverage of my choice......

 

[Kception]

Does anyone know - what we need to know for the oxygen activation lecture? So confused

Was it this bad last year?

 

[Nimbus2000]

start 10 min late.. mumble mumble "Dioxygenases" mumble, mumble "O2 activation, Kinetics, Lipid membrane, Peroxides" mumble mumble "Here's a formula that you don't need to know" .... "we can trap intermediates! (probably the most interesting thing in the lecture"

bolded = gold. that is what i learnt today. i literally, only heard dioxygenases, everything else, went flying through my head... i'm being serious, i don't recall him saying "we can trap intermediates" or even O2 Activation! LOL

as to what Kentception asked, i have no idea, lol sorry, was going to ask the same thing myself!

 

[Cathay]

Does anyone know - what we need to know for the oxygen activation lecture? So confused

Was it this bad last year?

As far as I can see the lecture slides are the exact same as last year's. I'd recommend having a brief read of the Module Summary Booklet if you happen to be a bit lost in the lecture slides.

 

[Bluerock]

Hey, could someone possibly explain this question to me? It's from the 2008 Terms test for Chemistry.
18. The rate constant was determined to be k = 6.7 × 10-4 L mol-1 s-1 for the following reaction
at 400 K.
2NOCl → 2NO + Cl2
Which of the following statements is CORRECT?
(A) The reaction is zero order.
(B) The reaction is first order.
(C) The reaction is second order.
(D) The reaction order cannot be determined because the concentration dependence of
NOCl with initial rate is not given.

Apparently the answer is B, but I don't see it?

 

[Sam]

Hey, could someone possibly explain this question to me? It's from the 2008 Terms test for Chemistry.
18. The rate constant was determined to be k = 6.7 × 10-4 L mol-1 s-1 for the following reaction
at 400 K.
2NOCl → 2NO + Cl2
Which of the following statements is CORRECT?
(A) The reaction is zero order.
(B) The reaction is first order.
(C) The reaction is second order.
(D) The reaction order cannot be determined because the concentration dependence of
NOCl with initial rate is not given.

Apparently the answer is B, but I don't see it?

Disregard, correct answer is below.

 

[hermafish]

Apparently the answer is B, but I don't see it?

Don't worry, the answers I have for that say that that's a typo, the right answer is C. (Definitely, due to the units of k)

 

[Sam]

Don't worry, the answers I have for that say that that's a typo, the right answer is C. (Definitely, due to the units of k)

Oh great, I didn't see that -.- I thought it was originally C based on units... But that was said to be wrong so I just figured it was my explanation. Durp! Thanks for the clearing up )