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Compounds A and B are antifreeze substances, when added at different concentrations (1st column) they drop the freezing temperature of water to the temperatures listed. So for the 3rd question, when the temperature is -6 degrees, basically any compound at any of the concentrations will prevent water from freezing since it drops the temperature below -6 degrees. For question 5, compound A seems to cap at a freezing point of -51 degrees, where as compound B caps at -48 degrees and actually is less effective when used in higher concentrations, so compound A does have a lower freezing point compared to compound B.Hello.
I don't quite understand this question. I was wondering if someone was able to explain it to me? What is the 2nd and 3rd column actually telling us?
View attachment 3747
View attachment 3748
So for example, compound A at 20% concentration will drop the water's freezing temperature to -7 degrees. If the external temperature is -6 degrees, this is technically "warmer" than -7 degrees, meaning the water will not freeze. The same goes for all the other concentrations for both compounds as it drops the temperature of the water lower than -6 degrees.But since the temperatures go below -6 degrees, doesn't that mean, the substances don't prevent the freezing? Since they're making the compounds more frozen?
I think what you're misunderstanding is what action the compounds have on water? They don't actually decrease the temperature of the water, they change the freezing point of water from its usual freezing temperature (0 degrees). Correct me if I'm wrong.But since the temperatures go below -6 degrees, doesn't that mean, the substances don't prevent the freezing? Since they're making the compounds more frozen?
Let incorrect answers be x. Then correct answers must be 24+x. We know:View attachment 3757Hi guys, would love if I could get some step by step working for these types of questions (algebra). Thanks
so all apples are red.... and the statement states that .. some apples are red, would this be YES or NO?
Condition: "Red cars without wheels have turbos."
Stem: "At least some red cars have turbos."
Personally I would say YES. The condition is alluding to the fact that there are red cars with wheels and red cars without wheels. Those with wheels may/may not have turbos. Those without wheels WILL have turbos. Thus the conclusion can be made that "At least some red cars have turbos".
![[MedStudentsOnline.com.au] UCAT: Decision Making [MedStudentsOnline.com.au] UCAT: Decision Making](https://data.medstudentsonline.com.au/attachments/3/3222-97bfa943db27780029c054af739d4b1b.jpg?hash=LnAnr3seOE)
its possible to do in 90 secs. i literally just eyeballed the problem.View attachment 3762
How do you even solve this question? Is it possible to do it in 90 sec? There are so many combinations!!
When you break it down like that, it seems so much easier! Thanks a lot =)its possible to do in 90 secs. i literally just eyeballed the problem.
1st bit of info. BC and S same consumption.
2nd but Coffee Lightest (thus 8kg)
3rd opening weight of S is heavier than BC but lighter than C. From Heaviest to Lightest itll be C>S>BC
4th V halved and C 2nd highest consumption. so we know that V (28 to 14)
now we know that because BC and S are same consumption, the closing minus opening are same thus (BC 15 to 13 and S 17 to 15. 2kg each)
now because V opening was 28 and BC and S have 15 and 17, C must start with 21 and must end with 16 (2nd highest consumption and heavier than S when starting)
21-16 is 5kg
Kind of a stupid question, but can many = all?
I also would like to know this? Does anyone know?
Yeah so basically x<5 or x>5 basically everything except x=5, which is clearly said in the stem.View attachment 3774
Hi, could someone please explain the last conclusion 'either more or less than'?? Does this not mean either more than 5 feet tall or less than 5 feet tall.
I see, I assumed that not equal to 5 is less than five. Thanks for the help!Yeah so basically x<5 or x>5 basically everything except x=5, which is clearly said in the stem.