UCAT: Decision Making

[fm8]

At your service - scroll down to the Decision Making Definitions > UCAT Subtests | UCAT Consortium

Not all = 1-99%
Some = An undetermined number being more than one but less than all.

(Btw shouldn't it be more than zero?)

oh i had no idea the definitions actually existed! Well that definitely solves the confusion

 

[Penny Lane]

The wording gets me on some of these questions. What are your thoughts on this DM question?

"Trains that run throughout the night, especially in London, are unsafe for passengers to take."

- Taking a bus would be a safer option - NO correct
- Only the trains in London can run at night - NO correct
- Trains running throughout the night are more dangerous than those running throughout the day - NO correct
- Trains running throughout the night in London are more unsafe than elsewhere - NO incorrect
- Trains in London are less safe than elsewhere - NO correct

I got one wrong but I really wasn't sure what option to select for the last two statements.

 

[cocodreams]

The wording gets me on some of these questions. What are your thoughts on this DM question?

"Trains that run throughout the night, especially in London, are unsafe for passengers to take."

- Taking a bus would be a safer option - NO correct
- Only the trains in London can run at night - NO correct
- Trains running throughout the night are more dangerous than those running throughout the day - NO correct
- Trains running throughout the night in London are more unsafe than elsewhere - NO incorrect
- Trains in London are less safe than elsewhere - NO correct

I got one wrong but I really wasn't sure what option to select for the last two statements.

Hey, I get what you mean about the last two options. They are contradictory because doesn't "more unsafe than elsewhere" = "less safe than elsewhere"? I reckon it's a bit of weirdly worded question. While it makes sense to say that the trains are "more unsafe than elsewhere" (it's true) but the fact they have written false for "less safe than elsewhere" is very weird! I think they would both be a 'Yes'. Is this your question about the wording?

 

[Penny Lane]

Hey, I get what you mean about the last two options. They are contradictory because doesn't "more unsafe than elsewhere" = "less safe than elsewhere"? I reckon it's a bit of weirdly worded question. While it makes sense to say that the trains are "more unsafe than elsewhere" (it's true) but the fact they have written false for "less safe than elsewhere" is very weird! I think they would both be a 'Yes'. Is this your question about the wording?

I'm not the only one then! Yeah. I seem to be getting tripped up on the wording of some of the questions and it is quite frustrating!

 

[fm8]

I'm not the only one then! Yeah. I seem to be getting tripped up on the wording of some of the questions and it is quite frustrating!

- Trains running throughout the night in London are more unsafe than elsewhere - YES?
- Trains in London are less safe than elsewhere - NO correct
I think this is what differentiates them, the first one specifies that it is the trains in London throughout the night, we dont know if day trains are more dangerous elsewhere, whereas the last one is saying that it is 'trains in London' ( so could be day or night)


I believe this section will be the death of me

 

[cocodreams]

Oh wow i missed that! Okay then it starts to make sense

- Trains running throughout the night in London are more unsafe than elsewhere - YES?
- Trains in London are less safe than elsewhere - NO correct
I think this is what differentiates them, the first one specifies that it is the trains in London throughout the night, we dont know if day trains are more dangerous elsewhere, whereas the last one is saying that it is 'trains in London' ( so could be day or night)


I believe this section will be the death of me

 

[Penny Lane]

Afternoon All I'm stuck on how to calculate this probability question. Anyone got any ideas?

Jill is watching Dave and Joe play a game. Dave and How have 3 coins each and must decide how many they will hold in their outstretched hand. Both players will know how many coins they are holding but not how many the other person holds.
Jill does not know how many coins either player is holding in their outstretched hand.
Jill guesses that there are a total of 5 coins in the two hands. Jill believes she has a 1 in 7 chance of being correct.
Is Jill right?

A. Yes, because there are a total of 7 possibilities
B. No, Jill has a 3 in 16 chance of being correct
C. No, Jill has a 1 in 8 chance of being correct
D. No, Jill has a 1 in 4 chances of being correct

Thanks guys!

 

[dotwingz]

Well there assuming there are 4 possible options for both Dave and Joe to hand out (0,1,2,3) means that there are 16 possibilities of coins

	0	1	2	3
0	0	1	2	3
1	1	2	3	4
2	2	3	4	5
3	3	4	5	6

Two of these 16 possibilities have 5 coins so P(5 coins) = 2/16 = 1/8

In an exam scenario, I wouldn’t bother with the table and just think internally what two numbers sum to 5

 

[fm8]

Afternoon All I'm stuck on how to calculate this probability question. Anyone got any ideas?

Jill is watching Dave and Joe play a game. Dave and How have 3 coins each and must decide how many they will hold in their outstretched hand. Both players will know how many coins they are holding but not how many the other person holds.
Jill does not know how many coins either player is holding in their outstretched hand.
Jill guesses that there are a total of 5 coins in the two hands. Jill believes she has a 1 in 7 chance of being correct.
Is Jill right?

A. Yes, because there are a total of 7 possibilities
B. No, Jill has a 3 in 16 chance of being correct
C. No, Jill has a 1 in 8 chance of being correct
D. No, Jill has a 1 in 4 chances of being correct

Thanks guys!

So I would right down all the different possibilities that could be reach from Joe and Daves decision to understand the process before simplifying 4 options means 16 possibilities.

So Outcomes could be:
D:1J:1.
D:1J:2
D:1J:3
D:2J:1
2:2
2:3 ---> 5
3:1
3:2 ----> 5
3:3
Also because each can hold none: 0:0 0:1. 0:2. 0:3. 1:0. 2:0. 3:0.
so there are a total of 16 possibilities
and there are 2 possibilities (of getting 5 from the two outstretched hands) out of the 16 in total; which equals 1/8

 

[Penny Lane]

Legends! I missed out including '0' as as option *facepalm*

 

[Rei]

This was on the consortium website; people keep asking this a lot.

 

[fm8]

Does anyone know where to find very challenging probability and Venn diagram questions? (content deleted) Just specifically maths probability and Venn diagrams that could even be harder or somewhat different to UCAT, like is there hsc excel books?

 

[Rei]

If it is for UCAT they wont go beyond year 9 level maths. Year 10 at best.

 

[sunnyrain]

.

 

[Scrivo_72]

Hi there.
I was wondering why the answer to this question wouldn't be D? Because I feel that it more directly links the increasing prices to the effect on the cigarette companies, rather than A which doesn't really link them directly.
View attachment 4596

Because D makes the assumption that there will be less customers if the price increases.

 

[dotwingz]

So the way I would approach this is that I would instantly knock out B and C.

A: Increased Prices --- (studies show) ---> no change in demand --> increased profits
D: Increased Prices --- (assumption/conjecture) ---> less demand ---> lowered profit

D seems alot more flimsy of an argument because they don't really talk about what evidence suggests that people will be buying less cigarettes, whilst A is pretty clear on what evidence supports their argument.

 

[fm8]

Hey so the thing that threw me off this question was the word "normally" I took that as, there could be times that chromosomes arn't visible, and the statement says chromosomes are visible, which is definitive.... does anyone else agree with it being no?

 

[emperortamarin]

Hey so the thing that threw me off this question was the word "normally" I took that as, there could be times that chromosomes arn't visible, and the statement says chromosomes are visible, which is definitive.... does anyone else agree with it being no?

View attachment 4598

I did this question a while ago and I agree.


Consider the following statements-

A: Chromosomes are always visible under a light in their condensed form - NO

firstly there is the normally argument
secondly, there could be other phases where they are in condensed form and are not visible

B: Chromosomes are sometimes visible under a light in their condensed form - YES
C: Chromosomes are never visible under a light in their condensed form - NO

I feel like the statement they gave is pretty dodgy since they never specified a timeframe (always, never, sometimes)

The only way I can see the answer being yes is if they said "chromosomes CAN be visible...."

 

[fm8]

I did this question a while ago and I agree.


Consider the following statements-

A: Chromosomes are always visible under a light in their condensed form - NO

firstly there is the normally argument
secondly, there could be other phases where they are in condensed form and are not visible

B: Chromosomes are sometimes visible under a light in their condensed form - YES
C: Chromosomes are never visible under a light in their condensed form - NO

I feel like the statement they gave is pretty dodgy since they never specified a timeframe (always, never, sometimes)

The only way I can see the answer being yes is if they said "chromosomes CAN be visible...."

Ok great! I don't feel like this issue would not occur in the actual ucat... hopefully lol

Thank you!

 

[SmartWorker]

For this question, how can i arrive at the answer, isn't the question missing information? (it doesn't mention how many customers??)